Count of vowels in a sting in oracle

In oracle 10 g we can do this by

SELECT length('akhil')
          - length(REGEXP_REPLACE('akhil','[a,e,i,o,u,A,E,I,O,U]','')) FROM DUAL;

In oracle 11g we can simplify this code to

SELECT REGEXP_COUNT('akhil','[a,e,i,o,u,A,E,I,O,U]' ) from dual

We can do this in any of the versions like 9i,10g,11g etc.. by

Select length('akhil')-length(translate('akhil','zaeiouAEIOU',z) ) from dual

The operation of the abouve statement is like below
       It will translate the each existance of 'z ' with z,because of there is nothing to be specified to replace for a,e,i,o,u,A,E,I,O,U . It will find the count of that. Reduce the count of this from the total length of the string . That is length of string -length of non vowel elements.

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